Supermarkets in Hanley, Canada

List of Supermarkets in Hanley, Saskatchewan: find addresses, phone numbers, email, social networks, photos, customer reviews and more.

Popular supermarkets in Hanley

0SELECT * FROM `locality` WHERE url = 'hanley-sk' LIMIT 1
1UPDATE locality SET weather = '{\"date\":\"2024-04-19\",\"data\":{\"2024-04-19\":{\"01\":{\"temp\":-5,\"pressure\":1029,\"humidity\":95,\"icon\":\"13n\",\"wind\":7},\"04\":{\"temp\":-5,\"pressure\":1029,\"humidity\":95,\"icon\":\"13n\",\"wind\":7},\"07\":{\"temp\":-6,\"pressure\":1031,\"humidity\":94,\"icon\":\"13d\",\"wind\":7},\"10\":{\"temp\":-6,\"pressure\":1034,\"humidity\":94,\"icon\":\"04d\",\"wind\":6},\"13\":{\"temp\":-5,\"pressure\":1035,\"humidity\":85,\"icon\":\"04d\",\"wind\":6},\"16\":{\"temp\":-3,\"pressure\":1035,\"humidity\":81,\"icon\":\"03d\",\"wind\":4},\"19\":{\"temp\":-3,\"pressure\":1034,\"humidity\":87,\"icon\":\"02d\",\"wind\":2},\"22\":{\"temp\":-11,\"pressure\":1036,\"humidity\":94,\"icon\":\"01n\",\"wind\":1}},\"2024-04-20\":{\"01\":{\"temp\":-13,\"pressure\":1037,\"humidity\":98,\"icon\":\"02n\",\"wind\":2},\"04\":{\"temp\":-13,\"pressure\":1036,\"humidity\":95,\"icon\":\"03n\",\"wind\":2},\"07\":{\"temp\":-13,\"pressure\":1035,\"humidity\":93,\"icon\":\"02d\",\"wind\":2},\"10\":{\"temp\":-5,\"pressure\":1033,\"humidity\":87,\"icon\":\"01d\",\"wind\":2},\"13\":{\"temp\":-0,\"pressure\":1031,\"humidity\":90,\"icon\":\"01d\",\"wind\":3},\"16\":{\"temp\":0,\"pressure\":1029,\"humidity\":101,\"icon\":\"03d\",\"wind\":3},\"19\":{\"temp\":-0,\"pressure\":1026,\"humidity\":92,\"icon\":\"03d\",\"wind\":3},\"22\":{\"temp\":-5,\"pressure\":1025,\"humidity\":82,\"icon\":\"01n\",\"wind\":3}},\"2024-04-21\":{\"01\":{\"temp\":-7,\"pressure\":1024,\"humidity\":82,\"icon\":\"01n\",\"wind\":3},\"04\":{\"temp\":-5,\"pressure\":1021,\"humidity\":80,\"icon\":\"01n\",\"wind\":3},\"07\":{\"temp\":-4,\"pressure\":1018,\"humidity\":78,\"icon\":\"01d\",\"wind\":4},\"10\":{\"temp\":1,\"pressure\":1014,\"humidity\":78,\"icon\":\"02d\",\"wind\":5},\"13\":{\"temp\":2,\"pressure\":1011,\"humidity\":92,\"icon\":\"03d\",\"wind\":6},\"16\":{\"temp\":3,\"pressure\":1008,\"humidity\":102,\"icon\":\"03d\",\"wind\":4},\"19\":{\"temp\":4,\"pressure\":1006,\"humidity\":102,\"icon\":\"04d\",\"wind\":3},\"22\":{\"temp\":3,\"pressure\":1005,\"humidity\":85,\"icon\":\"03n\",\"wind\":5}}}}' WHERE id = 18638 LIMIT 1
0SELECT * FROM `region` WHERE id = 179 LIMIT 1
0SELECT * FROM `category` WHERE url = 'supermarket' LIMIT 1
1SELECT locality_id, category_id, price_level FROM `category_item` WHERE locality_id = 18638 AND category_id = 102 GROUP BY locality_id, category_id, price_level
0SELECT COUNT(*) FROM `category_item` WHERE locality_id = 18638 AND category_id = 102
0SELECT * FROM category_item INNER JOIN item ON category_item.item_id = item.id WHERE category_item.locality_id = 18638 AND category_item.category_id = 102 ORDER BY item.name LIMIT 0,24
0SELECT * FROM `region` WHERE id IN ('179') LIMIT 1
0SELECT * FROM `locality` WHERE id IN ('18638') LIMIT 1
0SELECT * FROM `photos` WHERE `item_id` IN ('233682')
1SELECT item_id, category_id FROM `category_item` WHERE item_id IN ('233682')
0SELECT * FROM `category` WHERE id IN ('96','99','102') LIMIT 3
0SELECT locality_id, category_id FROM `category_item` WHERE locality_id = 18638 GROUP BY locality_id, category_id
0SELECT * FROM `category` WHERE `id` IN ('96','97','98','99','100','102','104','107','108','110','115','118','119','120','121','125','126','127','132','133','136','144','164','168','169') ORDER BY name
0SELECT * FROM counts where updated="2024-04-19" and table_name like 'news'
0SELECT * FROM counts where updated="2024-04-19" and table_name like 'news'
0SELECT * FROM `category` ORDER BY name
4SELECT * FROM `item` f JOIN ( SELECT RAND() * (SELECT MAX(id) FROM `item`) AS max_id ) AS m WHERE f.id >= m.max_id ORDER BY f.id ASC LIMIT 4
0SELECT * FROM `region` WHERE id IN ('178','176') LIMIT 2
0SELECT * FROM `locality` WHERE id IN ('17588','17949','16478') LIMIT 3
0SELECT * FROM `photos` WHERE `item_id` IN ('39487','39488','39489','39490')
0SELECT * FROM `locality` f JOIN ( SELECT RAND() * (SELECT MAX(id) FROM `locality`) AS max_id ) AS m WHERE f.id >= m.max_id ORDER BY f.id ASC LIMIT 7
0SELECT * FROM `region` WHERE id IN ('168') LIMIT 1